Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ia/paper-2/2a/iii/solution

Since
integration gives
Part (i) gives , so the tangent addition functional equation has the solutions
for constants such that no pole lies in . Conversely, the tangent addition formula verifies the functional equation. If , then , and
on any such interval, necessarily with .

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