 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ib/paper-1/9e/b/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

g H

is a fixed coset, then

xg H = g H .

Multiplying on the left by

g^{- 1}

gives

g^{- 1} xg H = H,

g^{- 1} xg \in H

. Thus

x is conjugate in G to an element of H .

 New to topics? Read the docs here!