 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ib/paper-2/6h/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

p_{j}

for the probability of face

j

H_{0} : p_{1} = \dots = p_{6} = \frac{1}{6}

against

H_{1} : at least one p_{j} \neq = \frac{1}{6} .

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