 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ib/paper-4/7h/b/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Starting from the airport, after one step the distribution is

(0, 1/2, 1/2)

. Multiplying once more by

P

gives

P (X_{2} = A) = \frac{3}{4}, P (X_{2} = B) = P (X_{2} = C) = \frac{1}{8} .

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