 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ii/paper-1/5l/c/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

In the Poisson GLM the responses are independent and

Y_{i} \sim Poisson (μ_{i}) .

The Poisson canonical link is logarithmic, so

lo g μ_{i} = x_{i}^{T} β, μ_{i} = e^{x_{i}^{T} β}, Var (Y_{i}) = μ_{i} .

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