 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ii/paper-1/7d/c/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

For

f (x) = 1/ (x^{2} + 1)

H f (y) = \frac{y}{1 + y ^{2}}

under the convention in part (b). Therefore

H f (- 1) = - \frac{1}{2} .

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