 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ii/paper-2/37b/d/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Let

ξ

be the forward reaction extent. Then

d N_{A} = - d ξ, d N_{B} = 2 d ξ, d N_{C} = d ξ .

At fixed

T, p

d G = μ_{A} d N_{A} + μ_{B} d N_{B} + μ_{C} d N_{C} = (- μ_{A} + 2 μ_{B} + μ_{C}) d ξ .

Minimization with respect to

ξ

μ_{A} = 2 μ_{B} + μ_{C} .

 New to topics? Read the docs here!