 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ii/paper-3/10e/b/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

The state is already

∣0 ⟩_{A} \otimes ∣0 ⟩_{B} \otimes ∣0 ⟩_{C} .

It therefore has Schmidt rank one across each of

A ∣ BC

B ∣ A C

, and

C ∣ A B

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