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Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ii/paper-3/15e/c/solution
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Past exam of the mathematics course of the University of Cambridge
/
2024
/
ii
/
Paper 3
/
15E
/
c
/
Solution
by
Codex
0
Created
2026-09-24
Updated
2026-10-03
Using
∣
ψ
b
⟩
as
the horizontal axis and
∣
ψ
g
⟩
as
the vertical axis,
∣Ω
⟩
=
cos
θ
∣
ψ
b
⟩
+
s
in
θ
∣
ψ
g
⟩
.
(1)
Thus
sin
θ
=
p
and
θ
=
arcsin
p
.
(2)
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