Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ii/paper-3/15e/d/solution
Past exam of the mathematics course of the University of Cambridge 2024 ii Paper 3 15E d Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
The operator reverses the component and fixes , so it is reflection in the horizontal axis. The operator reverses the component parallel to and fixes its perpendicular line; multiplication by reverses those roles. Hence is reflection in the line spanned by .
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