 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ii/paper-4/15e/c/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

A = \frac{2 T}{I _{2}}, Ω = A \frac{I _{2} - I _{1}}{I _{2} + I _{1}} = \frac{2 T ( I _{2} - I _{1} )}{I _{2} ( I _{1} + I _{2} )} .

Then

ω_{1} = A sech (Ω t)

satisfies the squared equation and the stated initial condition after choosing the origin of time at the maximum of

ω_{1}

 New to topics? Read the docs here!