 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ii/paper-4/28l/a/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

The identity

\frac{1}{n} \sum_{i = 1}^{n} (X_{i} - \overset{ˉ}{X}_{n})^{2} = \frac{1}{n} \sum_{i = 1}^{n} X_{i}^{2} - \overset{ˉ}{X}_{n}^{2}

and the weak law applied to

X_{i}

and

X_{i}^{2}

E X_{1}^{2} - μ^{2} = σ^{2} .

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