 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ii/paper-4/28l/b/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

n {g (\overset{ˉ}{X}_{n}) - g (μ)} \Rightarrow N (0, g^{'} (μ)^{2} σ^{2}) .

Thus one may take

σ_{n} = \frac{∣ g ^{'} ( μ ) ∣ σ}{n} .

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