 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ii/paper-4/4j/a/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

f : D \to D^{'}

f : Q \to Q^{'}

satisfying

f (q_{0}) = q_{0}^{'}, f (δ (q, a)) = δ^{'} (f (q), a)

for every state

q

a

, together with

q \in F ⟺ f (q) \in F^{'} .

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