 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ii/paper-4/6a/a/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

Of the

a_{t}

λ

leaves by maturation and the rest remains immature. Of the

b_{t}

μ

divides and is replaced by four immature cells, while a fraction

k

dies; the remainder stays mature. These contributions give exactly

a_{t + 1} = (1 - λ) a_{t} + 4 μ b_{t}, b_{t + 1} = λ a_{t} + (1 - μ - k) b_{t} .

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