Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/iii/paper-102/3/a/ii/solution
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 102 3 a ii Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
Write a positive nonsimple root asIf for every simple root with , thenwhich is impossible. Hence for some simple . The root-string property then gives , and its simple-root coefficients remain nonnegative. This is the simple-root subtraction lemma.
Induct on the height . Applying the induction hypothesis to and appending writesso that every partial sum is a root.
Finally let be simple and let be positive. In the simple-root expansion ofall coefficients except possibly that of are unchanged, and at least one of those unchanged coefficients is positive. Since a root has coefficients all of one sign, the image cannot be negative. Thus permutes , as stated by action of a simple reflection on positive roots.
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