 Solution

The Fourier density-increment proof of the Meshulam theorem controls three-term progressions through ordinary Fourier coefficients, equivalently the $U^2$ norm. Four-term progressions are controlled by the Gowers uniformity norm $U^3$. A function can have small correlation with every linear character while correlating strongly with a quadratic phase; such a function can have small $U^2$ norm but large $U^3$ norm. Ordinary Fourier uniformity therefore does not make the four-term progression count pseudorandom, and a large linear Fourier coefficient need not exist when that count is deficient. Quadratic or higher-order Fourier structure is needed.