 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/ia/paper-1/2c/c/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

For

b = (2, b, 0)^{T}

, compatibility gives

b = - 3

when

a = - 2

and

b = 2

when

a = 3

. The respective solution families are

x = (1, - 1, 0)^{T} + t (1, 1, 1)^{T}

and

x = (1, - 1, 0)^{T} + t (- 3/2, 7/2, 1)^{T},

where

t \in R

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