 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/ia/paper-1/9e/c/i/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

True. For

m > n

∣ a_{m} - a_{n} ∣ \leq \sum_{j = n}^{m - 1} d_{j}

. Convergence of

\sum d_{j}

makes this tail arbitrarily small, so

(a_{n})

is Cauchy and hence convergent.

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