 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/ia/paper-3/4a/i/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

The field is

e_{θ}

, so on the polar boundary

F \cdot d r = r d θ

. Hence

\oint_{C} F \cdot d r = \int_{- π}^{π} (1 + cos θ) d θ = 2 π .

 New to topics? Read the docs here!