 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/ia/paper-4/7d/c/i/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

True. If

p (a, a^{'}) = p (b, b^{'})

, then

a^{'} = b^{'}

, so

f (a) = g (a^{'}) = g (b^{'}) = f (b)

. Injectivity of

f

gives

a = b

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