 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/ib/paper-1/12/12-1g/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

f_{2} (z) = 2 \sum_{n = 0}^{\infty} \frac{( - 1 ) ^{n}}{n ! ( 2 n + 1 )} z^{- 2 n} .

There are infinitely many negative Laurent coefficients, so zero is an essential singularity.

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