 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/ib/paper-2/18h/d/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Take

N \geq 2

and

q_{2} = 1

. The chain alternates deterministically between zero and one, so

P (X_{n} = 0)

alternates between one and zero and does not converge.

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