 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/ii/paper-2/37c/b/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

With vibrations frozen out, each diatomic molecule has three translational and two rotational quadratic degrees of freedom. Equipartition therefore gives

E = \frac{5}{2} N k_{B} T .

p V = N k_{B} T

H = E + p V = \frac{7}{2} N k_{B} T .

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