 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/ii/paper-2/5k/2/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

No dominance says that mean yield is affine in the number of

A

μ_{aa} = α, μ_{A a} = α + δ, μ_{AA} = α + 2 δ .

Equivalently,

2 μ_{A a} = μ_{aa} + μ_{AA}

. Fit that reduced model and compare it with Model 1 using

r
model3 <- lm(yield ~ count, data = potato)
anova(model3, model1)

The resulting one-degree-of-freedom F-test tests the no-dominance constraint against unrestricted genotype means.

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