Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/iii/paper-129/1/b/solution
Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 129 1 b Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-24
Let be a subspace with much larger than , and choose linearly independent vectors whose images are independent modulo . SetThen , while is the union of , the disjoint cosets , and at most exceptional sums . HenceEvery subspace containing must contain and all , so it has at least elements. Thus the exponential dependence on in the Freiman-Ruzsa theorem over a finite field cannot in general be replaced by a subexponential one.
New to topics? Read the docs here!