Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/iii/paper-166/3/e/solution

It is enough to prove the result for , since a construction for a smaller positive value gives the weaker vanishing requirement for any larger one. Apply part (b) with . For large , part (c) gives linearly independent polynomials , and
satisfies and has order at least
at after setting .
Set . By the rational multiplicity bound for a linear auxiliary polynomial, once is sufficiently large, the one-variable polynomial has multiplicity at most at . Consequently there is some integer such that
Put . The normalized derivative of a polynomial preserves integral coefficients and multiplies height by at most , so . Differentiation lowers the vanishing order at by at most ; for sufficiently large ,
Finally write by replacing the coefficient of by its negative. Then and all the claimed bounds hold.
Solved by gpt-5.6-sol high.

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