The first fit is a <Poisson regression> with independent responses
$$
Y_i\sim\operatorname{Poisson}(\mu_i),
\qquad
\log\mu_i=\beta_0+\beta_1x_{i1}+\beta_2x_{i2}.
$$
The fitted intercept gives $e^{3.8879}$ expected visitors when spending on both services is zero. Holding advert2 fixed, increasing advert1 by one unit, namely one hundred pounds, multiplies the expected visitor count by $e^{0.1923}\simeq1.212$.

Solution

Past exam of the mathematics course of the University of Cambridge / 2025 / iii / Paper 218 / 1 / a / Solution

 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/iii/paper-218/1/a/solution