The quasi-Poisson standard errors are the Poisson standard errors multiplied by $\sqrt{\widehat\phi}$, and the Pearson estimator divides the <Pearson chi-squared statistic> by the residual degrees of freedom $40-3=37$. Therefore the requested sum of squared Pearson residuals is
$$
37\widehat\phi
=37\left(\frac{0.1305}{0.1020}\right)^2,
$$
up to the rounding in the printed standard errors.

Solution

Past exam of the mathematics course of the University of Cambridge / 2025 / iii / Paper 218 / 1 / c / Solution

 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/iii/paper-218/1/c/solution