 Solution

Let $H={\mathrm{Stab}}_F(x)$. The identity belongs to $H$ because $F(e,x)=x$. If $g,h\in H$, the group action law givesso $gh\in H$. Finally, if $g\in H$, thenso $g^{-1}\in H$. The subgroup criterion therefore proves that ${\mathrm{Stab}}_F(x)$ is the stabilizer subgroup of $x$.