 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/iii/paper-327/2/b/iv/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

True. Repeated use of the Leibniz rule and the polynomial Taylor formula gives

P (D) (f g) = \sum_{α} \frac{1}{α !} (D^{α} f) P^{(α)} (D) g .

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