 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ia/paper-1/6c/b/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

B x = 0 ⟺ A S x = 0 ⟺ x \in S^{- 1} (ker A)

; invertibility of

S

preserves dimension.

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