 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ia/paper-2/12f/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Conditioning on generation

n

and using independence gives

F_{n + 1} (s) = F_{n} (F_{1} (s))

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