 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ia/paper-2/12f/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Differentiating at

s = 1

gives

E X_{n + 1} = μ E X_{n}

, hence

E X_{n} = μ^{n}

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