 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ia/paper-3/11a/b/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

On a simply connected region,

\nabla \times E = 0

gives

E = - \nabla ϕ

. Then Gauss's law gives

\nabla^{2} ϕ = - ρ / ε_{0}

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