 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ia/paper-3/12a/d/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

It equals

C δ_{ij}

. Taking the trace gives

3 C = 4 π a^{4} e^{- a^{2}}

, hence

C = 4 π a^{4} e^{- a^{2}} /3

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