 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ia/paper-3/12a/e/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Expanding the integrand, the terms linear in

x

integrate to zero. Therefore

T_{ij} = \frac{4 π a ^{4} e ^{- a^{2}}}{3} δ_{ij} + 4 π a^{2} e^{- a^{2}} u_{i} v_{j},

so these are

α

and

β

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