 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ia/paper-4/12b/a/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

E_{e} = (m_{π}^{2} + m_{e}^{2}) c^{2} / (2 m_{π})

and

p_{e} = (m_{π}^{2} - m_{e}^{2}) c / (2 m_{π})

. Thus

v_{e} = c (m_{π}^{2} - m_{e}^{2}) / (m_{π}^{2} + m_{e}^{2})

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