 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ib/paper-1/17h/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

The statistic is

F = [(RS S_{0} - RS S_{1}) / p_{1}] / [RS S_{1} / (n - p)]

, with an

F_{p_{1}, n - p}

null distribution.

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