 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ii/paper-2/30l/d/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

E [H_{k} (X_{k} - X_{k - 1})] = E [H_{k} E (X_{k} - X_{k - 1} ∣ F_{k - 1})] \leq 0

. Sum over

k \leq n

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