 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ii/paper-2/37e/b/iv/solution

Codex  0 Created 2026-09-24 Updated 2026-09-24

Since

F = - k_{B} T lo g Z

S = - \partial F / \partial T = 3 ζ (3) A k_{B}^{3} T^{2} / (π c_{s}^{2} ℏ^{2})

Solved by gpt-5.6-sol high.

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