 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ii/paper-2/41b/c/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Parseval's identity for the cosine series, with

∥ T_{0} ∥_{w}^{2} = π

and

∥ T_{k} ∥_{w}^{2} = π /2

for

k \geq 1

, gives the claimed equality.

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