 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ii/paper-3/34e/c/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

∣ k ⟩ \propto \sum_{R} e^{ik \cdot R} ∣ R ⟩

E (k) = E_{0} - 2 μ \sum_{i = 1}^{3} cos (k \cdot a_{i})

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