 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ii/paper-3/35e/b/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Stirling and replacing the magnetization sum by an integral gives the stated form with

P (m) = - β (B m + 3 J m^{2} + 2 K m^{3})

, up to subexponential constants.

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