 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ii/paper-4/16j/b/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

From

ρ (x) = sup_{y \in x} (ρ (y) + 1)

, if every

ρ (y) < γ

, then every

ρ (y) + 1 \leq γ

and the supremum is at most

γ

, contradicting

γ < ρ (x)

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