Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ii/paper-4/20g/a/solution
Past exam of the mathematics course of the University of Cambridge 2026 ii Paper 4 20G a Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
The left side is the norm form for . Reducing a hypothetical equation modulo 7 and then descending through the forced divisibilities of gives an infinite descent, so only the zero solution exists. If , clearing denominators minimally and applying the norm equation would produce a forbidden nonzero integer solution; hence no such exists.
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