 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ii/paper-4/27k/a/iii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

The time-dependent Poisson mean tends to

λ / μ

, so each mass converges directly to

e^{- λ / μ} (λ / μ)^{k} / k! = π_{k}

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