 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/ii/paper-4/33a/b/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

L \cdot S = \frac{1}{2} (J^{2} - L^{2} - S^{2})

. Hence the coupled

∣ n ℓ s j j_{z} ⟩

basis diagonalizes the spin-orbit term.

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