 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/iii/paper-128/3/a/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

κ

and

λ

(κ^{+})^{λ} = κ^{λ} \cdot κ^{+} = max {κ^{λ}, κ^{+}} .

Equivalently,

ℵ_{α + 1}^{ℵ_{β}} = ℵ_{α}^{ℵ_{β}} \cdot ℵ_{α + 1} .

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