Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2026/iii/paper-139/2/a/solution
Past exam of the mathematics course of the University of Cambridge 2026 iii Paper 139 2 a Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-24
Schur lemma says that a homomorphism between simple modules is either zero or an isomorphism; consequently the endomorphism ring of a simple module is a division ring. Indeed, the kernel and image of a module homomorphism are submodules. Simplicity makes each either zero or the whole module, proving both assertions.
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